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After spending hours on this issue(well, about an hour), I finally got my program to work right <:] .

Anyways, there are no limits as to how you make it.

What happens - the user inputs two numbers(n and x).

number * n + number * x = the third number inputted. This can be a workaround to solving it on paper.

For example: the user inputs 2 and 3. He then inputs a number that he wants (number * n + number * x) to equal.

If you need a better explanation(as from looking at it... it is sort of lame :()

I will post my solution once another working solution has been posted.
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