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I missed a day of class, and I am slightly lost.

Problem says.

A bullet with initial velocity of 300 m/s is shot up at a 39 degrees angle.

I solved the part of the problem where it asks questions about the bullet landing in a same level ground, but I am completely lost in this next part of the question.

If the bullet landed on a platform 200 m high, how long was the bullet in the air?

I used the equation of

Vy squared = Vyo squared + 2gravity (Y-Yo)

In that case, I get the equation of

Vy = (35721 - 3920) squarerooted

Which gives me the answer of Vy = 178.

Then i plug 178 into Vy = Vyo + gravity time

Which gives me a total time of only 1 second.

Help?
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