Logarithm question

[Pulse]

I know it's a shitty maths thread, but this question is driving me mental.

If the following expression
3log(3)+2log(2)
is written in the form of log(x) what is the value of x?


Any help?

 

[dfc05]

The multipliers in front of the logs become exponents on the numbers:
3log(3) + 2log(2)
= log(3^3) + log(2^2)
= log(9) + log(4)

To add logs, you multiply the numbers:
log(9) + log(4)
= log(9*4)
= log(36)

=> x = 36

For your reference:
http://www.sosmath.com/algebra/logs/log4/log44/log44.html

Edit: Oops Minister is correct, I squared 3 instead of cubed. That is truly embarrassing.

 

[Minister]

I think x=108 yet not done logarithms in a while.

3log(3) can be written as log(3-cubed) = log(27)
2log(2) " " log(2-squared) = log(4)

log(27)+log(4) = log(27*4) = log(108)

Not sure though, that could be complete bullshit.

Edit: Started to reply before above post showed up.

 

[Pulse]

I think x=108 yet not done logarithms in a while.

3log(3) can be written as log(3-cubed) = log(27)
2log(2) " " log(2-squared) = log(4)

log(27)+log(4) = log(27*4) = log(108)

Not sure though, that could be complete bullshit.

Edit: Started to reply before above post showed up.

You were right, cheers!

 

[Druckles]

Damn, I squared three as well :angry:

Yeah, multiples are powered and log(a) + log(b) = log(ab), basically.

 

[Mr Stabby]

Are they all to the same base?

 

[Druckles]

Wut?

Yes, I assume they are, otherwise he would have specified which base.